1.

Evaluate: \(\int\frac{cos^2x.cotx}{4 + 5cos^2x}dx\)

Answer»

\(\int\frac{cos^2x.cotx}{4 + 5cos^2x}dx\)

\(\int\frac{\frac{-1}{10}dx}{t} = \frac{-1}{10}\)logt + c

= log(4 + 5cosec2x) + c 

put 4 + 5 cosec2x = t 

– 10 cosec x – cosec x × cot x dx = dt 

cosec2x . cotxdx = \(\frac{-1}{10}\)dt



Discussion

No Comment Found