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Evaluate: \(\int\frac{cos^2x.cotx}{4 + 5cos^2x}dx\) |
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Answer» \(\int\frac{cos^2x.cotx}{4 + 5cos^2x}dx\) = \(\int\frac{\frac{-1}{10}dx}{t} = \frac{-1}{10}\)logt + c = log(4 + 5cosec2x) + c put 4 + 5 cosec2x = t – 10 cosec x – cosec x × cot x dx = dt cosec2x . cotxdx = \(\frac{-1}{10}\)dt |
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