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Evaluate: \(\int\frac{cotx}{3 + log(sinx)}dx\) |
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Answer» \(\int\frac{cotx}{3 + log(sinx)}dx\) = \(\frac{dt}{t}\) = log t + c = log(3 + log(sin x)) + c put 3 + log(sin x) = t \(\frac{cosx}{sinx}dx\) = dt cos x dx = dt |
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