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Evaluate `int sin(logx)dx`.A. `(1)/(2)xsinlogx+(1)/(2)xcos(logx)+C`B. `(1)/(2)xsinlogx-(1)/(2)xcos(logx)+C`C. `-(1)/(2)xsin(logx)+(1)/(2)xcos(logx)+C`D. none of these |
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Answer» Correct Answer - B `I=int{sinunderset(I)((logx))*underset(II)1}dx=(sinlogx)x-int(cos(logx))/(x)*xdx` `=xsin(logx)-int{cosunderset(I)((logx))*underset(II)(1)}dx` `=xsin(logx)-cos(logx)*x+int(-sin(logx))/(x)*xdx` `:." "2I=xsin(logx)-xcos(logx)-C` |
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