1.

`int"cosec"xdx=?`A. `log|"cosec"x-cotx|+C`B. `-log|"cosec"x-cotx|+C`C. `log|"cosec "x+cotx|+C`D. none of these

Answer» Correct Answer - A
`I=int("cosec "x("cosec "x-cotx))/(("cosec "x=cotx))dx=int(1)/(t)dt," where " ("cosec" x-cot x)=t`.
`=log|t|+C=log|"cosec "x-cotx|+C`.


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