InterviewSolution
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`intsecxdx=?`A. `log|secx-tanx|+C`B. `-log|secx+tanx|+C`C. `log|secx+tanx|+C`D. none of these |
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Answer» Correct Answer - C `I=int(secx(secx+tanx))/((secx+tanx))dx=int(1)/(t)`dt, where (secx+tanx)=t. `=log|t|+C=log|secx+tanx|+C`. |
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