1.

`int((1+sinx))/((1+cosx))dx=?`A. `"tan"(x)/(2)+2log|"cos"(x)/(2)|+C`B. `"-tan"(x)/(2)+2log|"cos"(x)/(2)|+C`C. `"tan"(x)/(2)-2log|"cos"(x)/(2)|+C`D. none of these

Answer» Correct Answer - C
`I=int(1)/((1+cosx))dx+int(sinx)/((1+cosx))dx`.
`int(dx)/(2cos^(2)((x)/(2)))+int(2sin((x)/(2))cos((x)/(2)))/(2cos^(2)((x)/(2)))dx`
`=(1)/(2)sec^(2)(x)/(2)dx+int"tan"(x)/(2)dx`
`=intsec^(2)tdt+2tantdt," where "(x)/(2)=t`
`=tant-2log|cost|+C="tan"(x)/(2)-2log|"cos"(x)/(2)|+C`.


Discussion

No Comment Found