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`int((1+sinx))/((1+cosx))dx=?`A. `"tan"(x)/(2)+2log|"cos"(x)/(2)|+C`B. `"-tan"(x)/(2)+2log|"cos"(x)/(2)|+C`C. `"tan"(x)/(2)-2log|"cos"(x)/(2)|+C`D. none of these |
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Answer» Correct Answer - C `I=int(1)/((1+cosx))dx+int(sinx)/((1+cosx))dx`. `int(dx)/(2cos^(2)((x)/(2)))+int(2sin((x)/(2))cos((x)/(2)))/(2cos^(2)((x)/(2)))dx` `=(1)/(2)sec^(2)(x)/(2)dx+int"tan"(x)/(2)dx` `=intsec^(2)tdt+2tantdt," where "(x)/(2)=t` `=tant-2log|cost|+C="tan"(x)/(2)-2log|"cos"(x)/(2)|+C`. |
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