Evaluate:\(\int\sqrt{4-x^2}dx\)∫√{4 - x2}dx

1.	Evaluate:\(\int\sqrt{4-x^2}dx\)∫√{4 - x2}dx
Answer» We know that, \(\int\sqrt{a^2-x^2}dx\) = \(\frac{x}2\)\(\sqrt{a^2-x^2}\) + \(\frac{a^2}2\)sin^-1\(\frac{x}a\) + c \(\int\sqrt{2^2-x^2}dx\) = \(\frac{x}2\)\(\sqrt{4-x^2}\) + 2sin^-1\(\frac{x}2\) + c

Answer»

We know that,

\(\int\sqrt{a^2-x^2}dx\) = \(\frac{x}2\)\(\sqrt{a^2-x^2}\) + \(\frac{a^2}2\)sin^-1\(\frac{x}a\) + c

\(\int\sqrt{2^2-x^2}dx\) = \(\frac{x}2\)\(\sqrt{4-x^2}\) + 2sin^-1\(\frac{x}2\) + c

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