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Evaluate `lim_(xto 1//2) ((4x^(2)-1))/((2x-1))`. |
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Answer» Given, `underset(xto1//2)"lim"(4x^(2)-1)/(2x-1) = underset(xto1//2)"lim"(2x^(2)-1)/(2x-1)` `=underset(xto1//2)"lim"((2x+1)(2x-1))/((2x-1)) = underset(xto1//2)"lim"(2x+1)` `=2 xx 1/2 + 1=1+1=2` |
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