1.

Evaluate : ∫ sec2(7 - 4x)dx

Answer»

Given,

∫ sec2(7 - 4x)dx

Let 7 – 4x = t 

Differentiating on both sides we get, 

-4 dx = dt

dx = \(-\frac{1}{4}\) dt

Substituting it in ∫ sec2(7 - 4x)dx we get,

\(\int-\frac{1}{4}\) sec2t dt

= tan t + c 

= tan (7 - 4x) + c



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