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Evaluate : ∫ sec2(7 - 4x)dx |
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Answer» Given, ∫ sec2(7 - 4x)dx Let 7 – 4x = t Differentiating on both sides we get, -4 dx = dt dx = \(-\frac{1}{4}\) dt Substituting it in ∫ sec2(7 - 4x)dx we get, = \(\int-\frac{1}{4}\) sec2t dt = tan t + c = tan (7 - 4x) + c |
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