1.

Evaluate the following integrals :\(\int\)\(\frac{1}{x(3+log\,x)}\)dx

Answer»

Assume,

3 + logx = t 

d(3 + logx) = dt 

⇒ \(\frac{1}{x}\)dx = dt

Put t and dt in given equation we get,

⇒ ∫\(\frac{dt}{t}\)

= ln|t| + c. 

But,

t = 3 + logx 

= ln|3 + logx| + c



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