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Evaluate the following integrals :\(\int\)\(\frac{1}{x(3+log\,x)}\)dx |
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Answer» Assume, 3 + logx = t d(3 + logx) = dt ⇒ \(\frac{1}{x}\)dx = dt Put t and dt in given equation we get, ⇒ ∫\(\frac{dt}{t}\) = ln|t| + c. But, t = 3 + logx = ln|3 + logx| + c |
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