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Evaluate the following integrals :\(\int\)\(\frac{1}{x\,log\,x}\) dx |
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Answer» Assume, logx = t d(logx) = dt \(\frac{1}{x}\)dx = dt Put t and dt in given equation we get, ⇒ ∫\(\frac{dt}{t}\) = ln|t| + c. But, t = logx = ln| logx| + c |
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