1.

Evaluate the following integrals :\(\int\)\(\frac{1}{x\,log\,x}\) dx

Answer»

Assume,

logx = t 

d(logx) = dt 

\(\frac{1}{x}\)dx = dt 

Put t and dt in given equation we get,

⇒ ∫\(\frac{dt}{t}\)

= ln|t| + c. 

But,

t = logx 

= ln| logx| + c



Discussion

No Comment Found