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Evaluate the following integrals :\(\int\)\(\frac{2cos2x+sec^2x}{sin2x+tanx-5}\)dx |
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Answer» Assume, sin2x + tanx - 5 = t d(tanx + sin2x - 5) = dt (2cos2x + sec2x) dx = dt Put t and dt in given equation we get ⇒ \(\int\frac{dt}{t}\) = In|t| + c But, t = sin2x + tanx - 5 = ln|sin2x + tanx - 5| + c. |
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