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Evaluate the following integrals :\(\int \frac{sec^2\sqrt x}{\sqrt x}\)dx |
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Answer» Assume, √x = t d(√x) = dt ⇒ \(\frac{1}{2\sqrt x}\)dx = dt ⇒ \(\frac{1}{\sqrt x}\) = dt Substituting t and dt ⇒2 ∫ sec2t dt = 2 tan t + c But, √x = t ⇒2 tan(√x) + c. |
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