1.

Evaluate the following integrals :\(\int \frac{sec^2\sqrt x}{\sqrt x}\)dx

Answer»

Assume,

√x = t 

d(√x) = dt 

⇒ \(\frac{1}{2\sqrt x}\)dx = dt

⇒ \(\frac{1}{\sqrt x}\) = dt

Substituting t and dt 

⇒2 ∫ sec2t dt 

= 2 tan t + c 

But,

√x = t 

⇒2 tan(√x) + c.



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