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Evaluate the following integrals :\(\int\frac{sin(log\,x)}{x}\)dx |
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Answer» Assume, logx = t d(logx) = dt ⇒ \(\frac{1}{x}\) dx = dt Substituting t and dt ⇒ \(\int\)sint dt = - cost + c But, t = logx ⇒ cos(logx) + c. |
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