1.

Evaluate the following integrals :\(\int\frac{sin(log\,x)}{x}\)dx

Answer»

Assume,

logx = t 

d(logx) = dt 

⇒ \(\frac{1}{x}\) dx = dt

Substituting t and dt 

⇒ \(\int\)sint dt

= - cost + c 

But,

t = logx 

⇒ cos(logx) + c.



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