1.

Evaluate the following integrals : ∫ sin5x cos x dx

Answer»

Assume,

sinx = t 

d(sinx) = dt 

cosx dx = dt 

∴ Substituting t and dt in given equation we get

⇒ \(\int\)t5dt

⇒ \(\frac{t^6}{6}\) + c

But,

t = sinx

⇒ \(\frac{sin^6x}{6}\) + c



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