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Evaluate the indefinite integral:∫6x5-18x2+7 dx |
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Answer» \(\int (6x^5 -18x^2 + 7)dx\) \(= 6\int x^5 dx - 18\int x^2 dx + 7\int dx\) \(= 6\left(\frac{x^6}{6}\right)-18\left(\frac{x^3}3\right) + 7x + C\) \(= x^6 - 6x^3 + 7x + C\) |
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