InterviewSolution
Saved Bookmarks
| 1. |
Evaluate: ∫x2cosxdx. |
|
Answer» ∫x2cosxdx = x2 – ∫sinx(2x)dx = x2 -2∫xsinxdx = x2 - 2[x(-cos x) – ∫-cosxdx] = x2sinx + cosx – 2 sinx + c |
|