1.

Evaluate: ∫x2cosxdx.

Answer»

∫x2cosxdx = x2 – ∫sinx(2x)dx 

= x2 -2∫xsinxdx 

= x2 - 2[x(-cos x) – ∫-cosxdx] 

= x2sinx + cosx – 2 sinx + c



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