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Examine the following functions for continuity.(a) `f(x)=x-5` (b) `f(x)=1/(x-5)` (c) `f(x)=(x^2-25)/(x+5)`(d) `f(x)=|x-5|` |
Answer» (a) f(x) = x - 5 is a polynomial function. `:.` f(x) is contnuous for each real value . (b) f(x) ` = (1)/(x - 5) , x ne 5 ` which is the quotient of two polynomials and is not defined at x = 5 `:.` f(x) is contnuous for each real value of x (except x = 5). (c) f(x) = `(x^(2) - 25)/(x + 5), x ne - 5` `= ((x - 5) (x + 5))/(x + 5) = x -5` which is a polynomial function . `:.` f(x) is continous for all real value x = -5 . (d) f(x) =`|x - 5| ` `{:={(x -5, if x ge 5),(5 - x, if x lt 5):}` For x `ge ` 5, f (x) = x - 5 which is a polynomial function. `:.` f(x) is continuous for x `ge `5. For x `lt ` 5, f(x) = 5 - x which is a polynomial function. `:.` f(x) is ontinuous for x `lt` 5 Therefore, f(x) is continuous for all real value of x . |
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