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`x = "sin" t, y = "cos" 2t` |
Answer» `{:(x = "sin"t,|,y = "cos" 2t),(rArr (dx)/(dt) = "cos"t,|,rArr (dy)/(dt) = -2"sin" 2t):}` `therefore (dy)/(dx) = (dy//dt)/(dx//dt) = -(2"sin"2t)/("cos" t)` `= - (2 * 2 "sin"t "cos"t)/("cos"t) = -4"sin" t` |
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