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If `y=[x+sqrt(x^2+a^2)]^n` then prove that `(dy)/dx=(ny)/sqrt(x^2+a^2)` |
Answer» `y= [x+ sqrt(x^2 + a^2)]^n` `dy/dx = n(x+ sqrt(x^2 + a^2))^(n-1) (1 + (2x)/(2sqrt(x^2+a^2)))` `= n(x+ sqrt(x^2 + a^2))^(n-1) ((sqrt(a^2+x^2) + x)/(sqrt(a^2+x^2)))` `= (n(x+ sqrt(a^2+x^2))^n)/(sqrt(a^2+x^2))` `= (ny)/sqrt(a^2+x^2)` Answer |
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