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Explain the formation of covalent bonds in water molecule (H_(2)O). |
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Answer» Solution :Oxygen is a central atom in the molecule of water. The atomic number of oxygen is 8, so its electronic CONFIGURATION is `{:(K,L),(2,6):}`. Thus, oxygen has six electrons in its L SHELL. Therefore, it needs two more electrons to fill the L shell. Oxygen shares two of its valence electrons with one electron each of K shell of two hydrogen atoms to form a molecule of water `(H_(2)O)`. As a RESULT, oxygen atom of water attains the electronic configuration of its nearest noble gas neon (Ne), which has EIGHT electrons in its L shell, while hydrogen atom attains the electronic configuration of its nearest noble gas helium (He), which has two electrons in its K shell. Here, these valence electrons are depicted by dots or CROSSES is shown as follows: 
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