Explain the nature of resultant solution when 20 mL of 0.05 M NaOH is mixed with 10 mL of 0.1 N HCl solution at 25^(@)C. When 10 mL of this solution is diluted 100 times what is the change in pH ?

Explain the nature of resultant solution when 20 mL of 0.05 M NaOH is

1.	Explain the nature of resultant solution when 20 mL of 0.05 M NaOH is mixed with 10 mL of 0.1 N HCl solution at 25^(@)C. When 10 mL of this solution is diluted 100 times what is the change in pH ?
Answer» Solution :(i) calculation of net `H^(+)` ions concentration in themixture (ii) calculate of the DIFFERENCE of number of `H^(+) and OH^(-)` ions GENERATED from the given amount RESPECTIVE acid and base (III) determination of the pH of the given mixture at `25^(@)C` (iv) relation between the pH of the solution and its NATURE (v) relation between the nature of the solution and the effect of dilution