Explain the nature of the covalent bond using the bond formation in CH

1.	Explain the nature of the covalent bond using the bond formation in CH_(3)Cl.
Answer» Solution :`CH_(3)Cl` is chloromethane. It is made up of one carbon atom, three hydrogen atoms and one CHLORINE atom. Carbon atom has 4 outermost electrons, each hydrogen atom has 1 electron and chlorine has 7 outermost electrons. Carbon shares its FOUR outermost electrons with three hydrogen atoms and one chlorine atom to form `CH_(3)Cl` as FOLLOWS: Each atom in `CH_(3)Cl` has a noble gas electron arrangement. Carbon attains the nearest noble gas CONFIGURATION of neaon, hydrogen acquires the configuration of HELIUM while chlorine achieves the configuration of argon. Chloromethane contains three C-H and one C-Cl covalent bonds.

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