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Explain the parallel connection of series resistors. |
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Answer» Solution :(i) Let `R_(1)` and `R_(2)` be connected in PARALLEL to to give an effective resistance of RP1. (ii) If you consider a connection of a set of series resistors connected in a parallel circuit, we get a parallel - series circuit. (iii) Let `R_(1)` and `R_(2)` be connected in series to give an effective resistance of `R_(S1)`. (iv) Silimarly, let `R_(3)` and `R_(4)` be connected in series to give an effective resistance of `R_(S2)`. (v) Then, both of these serial segments are connected in parallel. Using equation `R_(S)=R_(1)+R_(2)+R_(3)` we get `R_(S)=R_(1)+R_(2)+R_(3)` `R_(S1)=R_(1)+R_(2)`, `R_(S2)=R_(3)+R_(4)` Finally, using equation, `(1)/(R_(p))=(1)/(R_(1))+(1)/(R_(2))+(1)/(R_(3))` the net effectiveresistance is GIVEN by `(1)/(R_("total"))=(1)/(R_(S1))+(1)/(R_(S2))` |
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