

InterviewSolution
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Express \(\frac {-3}{5}\) as a rational number with denominator(i) 20 (ii) -30 (iii) 35 (iv) -40 |
Answer» For a fraction,\(\frac {a}{b}\) \(\frac {a}{b}=\frac{a\times n}{b\times n}\) Where, n ≠ 0 (i) We have to express \(\frac{-3}{5}\) as a rational number with denominator 20. In order to make the denominator 20, multiply 5 by 4. Therefore, \(\frac{-3}{5}=\frac{-3\times4}{5 \times 4}\) \(\frac{-3}{5}=\frac{-12}{20}\) (ii) We have to express \(\frac{-3}{5}\) as a rational number with denominator -30. In order to make the denominator -30, multiply 5 by -6. Therefore, \(\frac{-3}{5}=\frac{-3\times-6}{5\times-6}\) \(\Rightarrow\) \(\frac{-3}{5}=\frac{18}{-30}\) (iii) We have to express \(\frac{-3}{5}\) as a rational number with denominator 35. In order to make the denominator 35, multiply 5 by 7. Therefore, \(\frac{-3}{5}=\frac{-3\times7}{5\times7}\) \(\Rightarrow\) \(\frac{-3}{5}=\frac{-21}{35}\) (iv) We have to express\(\frac{-3}{5}\) as a rational number with denominator -40. In order to make the denominator 20, multiply 5 by -8. Therefore, \(\frac{-3}{5}=\frac{-3\times-8}{5\times-8}\) \(\Rightarrow\) \(\frac{-3}{5}=\frac{24}{-40}\) |
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