

InterviewSolution
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Express \(\frac{-3}{5}\) as a rational number with denominator(i) 20 (ii) -30 (iii) 35 (iv) -40 |
Answer» For a fraction, \(\frac{a}{b}\) \(\frac{a}{b} = \) \(\frac{a\times{n}}{b\times{n}}\) Where, n ≠ 0 (i) We have to express \(\frac{-3}{5}\) as a rational number with denominator 20. In order to make the denominator 20, multiply 5 by 4. Therefore, \(\frac{-3}{5}\) = \(\frac{-3\times4}{5\times4}\) \(\Rightarrow\) \(\frac{-3}{5}\) = \(\frac{-12}{20}\) (ii) We have to express \(\frac{-3}{5}\) as a rational number with denominator -30. In order to make the denominator -30, multiply 5 by -6. \(\frac{-3}{5}\) = \(\frac{-3\times4}{5\times-6}\) \(\Rightarrow\) \(\frac{-3}{5}\) = \(\frac{18}{-30}\) (iii) We have to express \(\frac{-3}{5}\) as a rational number with denominator 35. In order to make the denominator 35, multiply 5 by 7. Therefore, \(\frac{-3}{5}\) = \(\frac{-3\times7}{5\times7}\) \(\Rightarrow\) \(\frac{-3}{5}\) = \(\frac{-21}{35}\) (iv) We have to express \(\frac{-3}{5}\) as a rational number with denominator -40. In order to make the denominator 20, multiply 5 by -8. Therefore, \(\frac{-3}{5}\) = \(\frac{-3\times8}{5\times-8}\) \(\Rightarrow\) \(\frac{-3}{5}\) = \(\frac{24}{-40}\) |
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