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`f(x)=e^(2x),f(x+deltax)=e^(2(x+deltax))` |
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Answer» `therefore f(x+deltax)-f(x)=e^(2(x+deltax))-e^(2x)=e^(2x)(e^(deltax-1))` `therefore (d)/(dx)(e^(2x))=underset(deltax to 0)lim (f(x+deltax)-f(x))/(deltax)=underset(x to 0)lim (e^(2x)(edeltx-1)/(deltax))` अंत: `e^(x)` का विस्तार प्रयोग करते हुए। |
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