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f(x)=sin 2x का मूल नियमो से प्रथम अवलंकन गुणांक ज्ञात कीजिएः |
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Answer» y=sin 2x ....(i) `therefore y+deltay=sin 2(x+deltax)` ....(i) `therefore y+deltay-y=sin 2(x+deltax)-sin 2x` `Rightarrow deltay=2cos (2x+delx)sin delta` `[therefore sin C-sin D =2cos"" (C+D)/(2)sin ""(C-D)/(2)]` दोनों पक्षों को `deltax` से भाग देकर `underset(deltax to 0)lim` लेने पर `underset(deltax to 0)lim (deltay)/(deltax)=(dy)/(dx)` `=underset(deltax to 0)lim 2cos(2x+deltax)(sin deltax)/(deltax)` `=2cos (2x+0)xx 1" "(therefore underset(theta to 0)lim (sin theta)/(theta)=1)` =2cos 2x `therefore (d)/(dx) sin 2x=2cos 2x` |
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