1.

Find a vector perpendicular to vector `vecA=(hati+2hatj-3hatk)` as well as `vecB=(hati+hatj-hatk)`

Answer» `vecC=vecAxxvecB=|{:(hati,hatj,hatk),(1,2,-3),(1,1,-1):}|=hati(-2+3)+hatj(-3+1)+hatk(1-2)`
`=hati-2hatj-hatk`
Hint. `vecC=vecAxxvecB`


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