`"Find "(dy)/(dx)" for "y=sin(x^(2)+1).`

1.	`"Find "(dy)/(dx)" for "y=sin(x^(2)+1).`
Answer» `"Let "y= sin(x^(2)+1).` Putting `u=x^(2)+1," we get y sin u"` `therefore" "(dy)/(dx)=cos u and (du)/(dx) = 2x` `"Now, "(du)/(dx)=(dy)/(du).(du)/(dx)` `= (cos u) (2x)=2x cos(x^(2)+1)`

Discussion

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