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Find `(dy)/(dx)`, if `y=sin^(-1)x+sin^(-1)sqrt(1-x^2),-1lt=xlt=1`. |
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Answer» Let `x = sintheta`, then `sin^-1x = theta` Then, our given equation becomes, `y = theta+sin^-1(sqrt(1-sin^2theta))` `y = theta+sin^-1(costheta)` `y = theta+sin^-1(sin(pi/2-theta))` `y = theta+pi/2 -theta` `y = pi/2` `:. dy/dx = 0` |
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