Find `(dy)/(dx)ifx=a(theta-sintheta)a n dy=a(1-costheta)dot`

1.	Find `(dy)/(dx)ifx=a(theta-sintheta)a n dy=a(1-costheta)dot`
Answer» `"We have "x=a(theta-sin theta)and y=a (1- cos theta).` `therefore" "(dx)/("d"theta)=a(1-cos theta) and (dy)/("d"theta)=a sin theta` `"or "(dy)/(dx)=(dy//"d" theta)/(dx//"d" theta)` `=(a sin theta)/(a(1-cos theta))` `=(2sin (theta//2)cos (theta//2))/(2 sin^(2) (theta//2))` `=cot""(theta)/(2)`

Discussion

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