1.

Find `(dy)/(dx)`, when: `x^(2)+y^(2)=log(xy)`

Answer» Correct Answer - `(y(1-2x^(2)))/(x(2y^(2)-1))`
`x^(2)+y^(2)=logx+logy`
`rArr2x+2y(dy)/(dx)=(1)/(x)+(1)/(y).(dy)/(dx).`


Discussion

No Comment Found