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Find `(dy)/(dx)`, when: `x^(2)+y^(2)=log(xy)` |
Answer» Correct Answer - `(y(1-2x^(2)))/(x(2y^(2)-1))` `x^(2)+y^(2)=logx+logy` `rArr2x+2y(dy)/(dx)=(1)/(x)+(1)/(y).(dy)/(dx).` |
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