Find `(dy)/(dx),`when`x=a(theta+sintheta)a n dy=a(1-costheta)`

1.	Find `(dy)/(dx),`when`x=a(theta+sintheta)a n dy=a(1-costheta)`
Answer» `x = a(theta+sintheta)` `:. dx/(d theta) = a(1+cos theta)` `y = a(1-cos theta)` `:. dy/( d theta) = asin theta` `:. dy/dx = (dy/( d theta))/(dx/( d theta)) = ( asin theta)/(a(1+cos theta))` `=>dy/dx = sin theta/(1+cos theta) = (2sin(theta/2)cos (theta/2))/(2cos^2(theta/2)) = tan(theta/2)` `=>:. dy/dx = tan(theta/2)`.

Discussion

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