Find `(dy)/(dx)`, when: `xylog(x+y)=1`

1.	Find `(dy)/(dx)`, when: `xylog(x+y)=1`
Answer» Correct Answer - `(-(x+y+x^(2)y))/(x^(2){y+(x+y)log(x+y)})` `ylog(x+y)=(1)/(x)` `rArry.(1)/((x+y)).(1+(dy)/(dx))+log(x+y).(dy)/(dx)=(-1)/(x^(2))` `rArr {(y)/((x+y))+log(x+y)}.(dy)/(dx)=-((1)/(x^(2))+(y)/(x+y)).`

Discussion

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