Find `(dy)/(dx)`, when `y=e^(a x)cos(b x+c)`

1.	Find `(dy)/(dx)`, when `y=e^(a x)cos(b x+c)`
Answer» We have `(dy)/(dx)=e^(ax).(d)/(dx){cos(bx+c)}+cos(bx+c).(d)/(dx)(e^(ax))` `=e^(ax).{-b sin(bx+c)}+cos(bx+c).ae^(ax)` `=e^(ax).{a cos (bx+c)-b sin (bx+c)}`.

Discussion

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