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Find `(dy)/(dx)`, when: `y=sin2x sin 3x sin 4x` |
Answer» Correct Answer - `(sin2x sin 3x sin 4x)(2cot 2x+3 cot 3x+4 cot 4x)` `logy=logsin2x+log sin 3x+log sin 4x` `rArr(1)/(y).(dy)/(dx)={(2cos2x)/(sin 2x)+(3cos3x)/(sin3x)+(4 cos 4x)/(sin 4x)}.` |
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