Find dy/dx: x2/a2 + y2/b2 = 1

1.	Find dy/dx: x2/a2 + y2/b2 = 1
Answer» Given as x²/a² + y²/b² = 1 Differentiating the equation on both sides with respect to x, 2x/a² + (2y/b²)(dy/dx) = 0 dy/dx = -xb²/ya²

Answer»

Given as x²/a² + y²/b² = 1

Differentiating the equation on both sides with respect to x,

2x/a² + (2y/b²)(dy/dx) = 0

dy/dx = -xb²/ya²

Discussion

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