1.

Find electric current draw (figure) from the battery of emf 12V.

Answer»

Solution :Let `I=I_(1)+I_(2)` be the current drawn from emf 12V. From the FIGURE, using the LOOP law. For the loop DABCD.
`-3(I_(1)+I_(2))+12-2I_(1)-5=0.......(a)`
for the loop DAFED.
`-3(I_(1)+I_(2))+12-4I_(2)=0.......(B)`
SOLVING the EQUATIONS (a) and `I_(2)=1.5A`
Total current drawn is then I = 0.5 + 1.5 = 2A


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