1.

Find \(\frac{dy}{dx}\), if x=9t^4 and y=t.(a) \(\frac{1}{36t^3}\)(b) \(\frac{1}{36t^2}\)(c) \(\frac{-1}{36t^3}\)(d) \(\frac{1}{32t^3}\)I had been asked this question during an online interview.My query is from Derivatives of Functions in Parametric Forms in division Continuity and Differentiability of Mathematics – Class 12

Answer»

The correct ANSWER is (a) \(\FRAC{1}{36t^3}\)

The BEST I can explain: Given that, x=9t^4 and y=t

\(\frac{DX}{dt}\)=36t^3

\(\frac{dy}{dt}\)=1

∴\(\frac{dy}{dx}\)=\(\frac{dy}{dt}.\frac{dt}{dx}=\frac{1}{36t^3}\)



Discussion

No Comment Found

Related InterviewSolutions