1.

Find \(\frac{dy}{dx}\) of 2x+3y = sinx.(a) \(\frac{cosx-2}{3}\)(b) \(\frac{cosx-2}{2}\)(c) \(\frac{cosx-3}{2}\)(d) \(\frac{sinx-2}{3}\)This question was addressed to me in an interview for internship.The query is from Differentiability in portion Continuity and Differentiability of Mathematics – Class 12

Answer»

The CORRECT answer is (a) \(\frac{cosx-2}{3}\)

Easiest EXPLANATION: Differentiating on both SIDES we GET 2 + 3\(\frac{dy}{DX}\) = cosx.

3\(\frac{dy}{dx}\) = cosx-2.

\(\frac{dy}{dx} = \frac{cosx-2}{3}\).



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