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Find how the volume density of the elastic deformation energy is distributed in a steel rod depending on the distance r from its axis. The length of the rod is equal to l, the torsion angle to `varphi`. |
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Answer» The energy between radii r and `r+dr` is, by differentiation, `(pir^3dr)/(l)Gvarphi^2` Its density is `(pir^3dr)/(2pirdrl)(Gvarphi^2)/(l)=1/2(Gvarphi^2r^2)/(l^2)` |
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