1.

Find mean deviation for the following data about median: {:("Class Interval",5-9,10-14,15-19,20-24,25-29),(f,5,9,12,8,6):}

Answer»

Solution :
`(N)/(2) = (40)/(2) = 20, L = 14.5, F = 14, f = 12, C = 5`
`"Median" = L + ((N/2)-f)/(f) xx C`
`=14.5 + (20-14)/(12) xx 5`
`=14.5 + 2.5 = 17`
`therefore "MD" = (Sum f|x - bar(x)|)/(N) "or" (sum fD)/(N)`
`= (195)/(40) = 4.875`.


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