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Find mean deviation for the following data about median: {:("Class Interval",5-9,10-14,15-19,20-24,25-29),(f,5,9,12,8,6):} |
Answer» Solution :![]() `(N)/(2) = (40)/(2) = 20, L = 14.5, F = 14, f = 12, C = 5` `"Median" = L + ((N/2)-f)/(f) xx C` `=14.5 + (20-14)/(12) xx 5` `=14.5 + 2.5 = 17` `therefore "MD" = (Sum f|x - bar(x)|)/(N) "or" (sum fD)/(N)` `= (195)/(40) = 4.875`. |
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