InterviewSolution
Saved Bookmarks
| 1. |
Find out the following in the electric circuit given in the figure. (i) Effective resistance of two 8 Omega resistors In the combination (ii) Current flowing through 4 Omega resistor (iii) Potential difference across 4Omega resistor (iv) Power dissipated in 4Omega resistor (v) Difference in reading of ammeter A_(1) and A_(2) ( if any) . |
|
Answer» <P> Solution :(i) Effective resistance of TWO `8Omega` resistors`(1)/(R)=(1)/(8) +(1)/(8)=(2)/(8)` `R=4 Omega` (ii) Current flowing through the CIRCUIT = current flowing though `4Omega` Equivalent resistance of the circuit =` 4 Omega+ 4 Omega` `= 8 Omega` Current flowing in the circuit `= (V)/(R) = (8V)/(8 Omega)= 1 A ` (iii) Potential difference across `4Omega = V_(1) = IR_(1)` `= 1A xx4 Omega= 4V ` (iv) POWER dissipated in `4 Omega= P = VI = 4 V xx1 A ` = 4 watt (v) Both `A_(1)` and `A_(2)` show same reading because current remains same in series combination. |
|