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Find out the number of waves made by a bohr electron is one complete revolation in its third orbit |
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Answer» For an electron to be in a particular energy level of radius r, with de brogle wavelength `lambda` `2pi r = n lambda` (where n is the number of weaves in one revolution `lambda = (h)/(mv)` `rArr n = (2 pi rm v)/(h)` For third orbit `r = 0.53 xx 10^(-10) (n)^(2)m V = 2.165 xx 10^(6) xx ((1)/(n))` `= 0.53 xx 10^(-10) xx (3)^(2)m = 2.165 xx 10^(6) xx (1)/(3)` `= 4.77 xx 10^(-10)m = 0.721 xx 10^(6)` Subsuitating the value of `r,v and h` we get `n = (2 pi rmv)/(h)` `= (2 xx 3.14 xx 4.77 xx 10^(-10) xx 0.721 xx 10^(6) xx 9.1 xx 10^(-31))/(6.626 xx 10^(-34))` |
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