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Find out the weight of `H_(2)SO_(4)` in `150 mL, (N)/(7)H_(2)SO_(4)`. |
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Answer» `N = ("Weight in gram")/("equivalent weight" xx volume("in"))` wt. in gram = eq. wt `xx N xx` volume `= 49 xx (1)/(7) xx (150)/(1000) = (21)/(20) = 1.05 g` |
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