Find second orderderivative of `log(logx)`

1.	Find second orderderivative of `log(logx)`
Answer» Let `y=log(logx).` Then, `(dy)/(dx)=(1)/((logx)).(1)/(x)=(1)/((xlogx))=(xlogx)^(-1)` `rArr(d^(2)y)/(dx^(2))=(d)/(dx)(x logx)^(-1)` `=(-1)(xlogx)^(-2).(d)/(dx)(xlogx)` `=(-1)/((xlogx)^(2)).(x.(1)/(x)+logx.1)=(-(1+logx))/((xlogx)^(2)).`

Discussion

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