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Find sideslip angle if [u, v, w] = [100, 5, 2.5]. Consider steady level flight.(a) 2.86°(b) 4.5°(c) 4.7°(d) 2.1°I had been asked this question during an interview.The doubt is from Lateral-Directional Static Stability and Control topic in portion Stability, Control, and Handling Qualities of Aircraft Design

Answer»

Right answer is (a) 2.86°

The BEST EXPLANATION: GIVEN, v = 5, V = [u^2+v^2+w^2] ^0.5 = [100*100+5*5+2.5*2.5] ^0.5 = 100.156.

Sideslip ANGLE = ARCSINE (v/V) = arcsine (5/100.156) = 2.86°.



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