1.

Find the 12th term from the end of the AP`-2, -4, -6, …, -100.`

Answer» Given AP, `-2,-4,-6, …, -100`
Here, first term (a)`=-2`, common difference (d)`=-4-(-2)= -2` and the last term (l)`= -100.`
We know that, the `n`th term `a_(n)` of an AP from the end is `a_(n)=l-(n-1)d,` where `l` is the last term and d is the common difference.
` :. ` 12th term from the end,
`a_(12)= -100-(12-1)(-2)`
` " " = -100+(11)/(2)= -100 +22= -78`.
Hence, the 12th term from the end is `-78`


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