Find the angle between two lines whose directionratios are proportiona – InterviewSolution

InterviewSolution

1.	Find the angle between two lines whose directionratios are proportional to `1,1,2a n d(sqrt(3)-1),(-sqrt(3)-1),4`.
Answer» Correct Answer - `(pi)/(3)` `sqrt(1^(2)+1^(2)+2^(2))=sqrt6 and sqrt((sqrt3-1)^(2)+(-sqrt3-1)^(2)+4^(2))=sqrt24`. `therefore costheta={(1)/(sqrt6)xx((sqrt3-1))/(sqrt24)+(1)/(sqrt6)xx((-sqrt3-1))/(24)+(2)/(sqrt6)xx(4)/(sqrt24)}` `=((sqrt3-1))/(12)+((-sqrt3-1))/(12)+(8)/(12)=(6)/(12)=(1)/(2)` `therefore theta = (pi)/(3)`.

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